##### Write a program that generate 6*6 two-dimensional matrix, filled with 0’s and 1’s , display the matrix, check every raw and column have an odd number’s of 1’s.
```				```
import java.util.Scanner;
class Practical_11 {
public static int[][] create_fill_matrix() {
int[][] matrix = new int[6][6];
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 6; j++) {
matrix[i][j] = (int)((Math.random() * 5) % 2);
}
}
return matrix;
}
public static void displayMatrix(int[][] matrix) {
System.out.print("\nMatrix Values \n");
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 6; j++) {
System.out.print(matrix[i][j] + " ");
}
System.out.println();
}
}
public static void main(String[] args) {
int my_matrix[][];
int i, j, cnt;
my_matrix = create_fill_matrix();
displayMatrix(my_matrix);
System.out.println("\nRows Having ODD no of 1s");
for (i = 0; i < 6; i++) {
cnt = 0;
for (j = 0; j < 6; j++) {
if (my_matrix[i][j] == 1) {
cnt++;
}
}
if (cnt % 2 != 0) {
System.out.println("Row - " + (i + 1) + " have ODD no of 1s");
}
}
System.out.println("\nColumns Having ODD no of 1s");
for (i = 0; i < 6; i++) {
cnt = 0;
for (j = 0; j < 6; j++) {
if (my_matrix[j][i] == 1) {
cnt++;
}
}
if (cnt % 2 != 0) {
System.out.println("Column - " + (i + 1) + " have ODD no of 1s");
}
}
}
}
```
```